An ideal gas at 2.0 atm pressure and 298 K temperature has a volume of 12.0 L. If the volume is decreased to 4.0 L and the temperature is held constant, what is the new pressure of the the gas in atm
Added by Henry F.
Step 1
We can plug in the given values for P1, V1, and V2: (2.0 atm x 12.0 L)/298 K = (P2 x 4.0 L)/298 K Simplifying, we get: P2 = (2.0 atm x 12.0 L)/4.0 L = 6.0 atm Show more…
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