4 mi, BC = 1.3 mi, and $\angle C = 111^\circ$. We want to find the length of AB, which we denote as $c$. We can use the Law of Cosines to solve for $c$:
$c^2 = a^2 + b^2 - 2ab \cos C$
where $a = BC = 1.3$ mi, $b = AC = 0.4$ mi, and $C = 111^\circ$.
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