Question

An object attached to a spring undergoes simple harmonic motion. A mass of 17 kilograms stretches the spring 0.7 meters. Use this information to find the spring constant. (Use $g = 9.8$ meters/second$^2$) (Round all answers/coefficients to 4 decimal places) $k = $ The previous mass is detached from the spring and a mass of 15 kilograms is attached. This mass is displaced 0.6 meters above equilibrium and then launched with an initial velocity of $-1$ meters/second. Write the equation of motion in the form $y(t) = c_1 \cos(\omega t) + c_2 \sin(\omega t)$. Do not leave unknown constants in your equation. $y(t) = $ Rewrite the equation of motion in the form $y(t) = A \cos(\omega t - \phi)$. Do not leave unknown constants in your equation. $y(t) = $

          An object attached to a spring undergoes simple harmonic motion. A mass of 17 kilograms stretches the spring 0.7 meters.
Use this information to find the spring constant. (Use $g = 9.8$ meters/second$^2$)
(Round all answers/coefficients to 4 decimal places)
$k = $
The previous mass is detached from the spring and a mass of 15 kilograms is attached. This mass is displaced 0.6 meters above equilibrium and then launched with an initial velocity of $-1$ meters/second. Write the equation of motion in the form $y(t) = c_1 \cos(\omega t) + c_2 \sin(\omega t)$. Do not leave unknown constants in your equation.
$y(t) = $
Rewrite the equation of motion in the form $y(t) = A \cos(\omega t - \phi)$. Do not leave unknown constants in your equation.
$y(t) = $

an object attached to a spring undergoes simple harmonic motion a mass of 17 kilograms stretches the spring 07 meters use this information to find the spring constant use g 98 meterssecond2 25294

Added by Brian D.

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