00:02
In this question, it is about simple harmonic motion.
00:05
We have an object, we are given that the amplitude is 140 m, which is 14 cm.
00:20
And then the period is 1 .3334 times 10 to the negative 3 minutes.
00:30
It's good to convert to si units, so 0 .08 seconds.
00:36
And then there are two parts in this question.
00:41
We need to find a displacement to write out the function for the displacement of the object in cia.
00:48
And then probably we need to find the displacement of the object at t.
00:52
Over 5 the t is the period okay so solution okay so in heart a we want to find the when to write down the displacement function so we'll use using x equals to a gosy omega t plus five okay this is the general expression for the simple harmonic motion okay the displacement function of the synchronic function.
01:29
Okay, so we need to cut the omega, which has 2 pi over a bt period, so 2 pi devoured 0 .08, then you get 78 .5 radiance per second, and then the next thing we need to find is phi because we have the mpcube, and we are given that at x equals to 0 x equals to 0 .07 meters and so 0 .07 equals to 0 .14...