An object is dropped from a height of 75 m above ground...

An object is dropped from a height of 75 m above ground level. Part (a) Determine the distance traveled, in meters, during the first second. Part (b) Determine the final speed, in meters per second, at which the object hits the ground. Part (c) Determine the distance, in meters, traveled during the last second of motion before hitting the ground.

Transcript

0:00 Hello everyone.

00:01 In this question a ball is dropped above the ground at a height of 75 meters.

00:06 So let's say this is the ball.

00:08 Its initial velocity is zero because it is released and it is released from a height of 75 meter above the ground.

00:16 So this height is 75 meter.

00:18 Now in the first part of question we have to find out that what exactly is the displacement in the first second? n and first second.

00:33 Okay, so basically we have to find out the displacement from t is equals to 0 to t is equals to 1.

00:38 That means for a time interval of 1 second.

00:41 So displacement will be given by u t plus half a t square from equation of motion i can write this but since initial velocity is 0 so i can write displacement as 1 by 2 n2 during this whole motion acceleration of the block will be acceleration of ball will be 9 .8 meter per second square so this will be half into 9 .8 into t is one second so it's one square 9 .8 divided by 2 is coming out as 4 .9 meter this is the displacement in the first second now in the second part of question we have to find out velocity of ball with which it will strike the ground so here let's say the velocity is v we have to find out the value of v so again i can apply the equation of motion which is v square minus u square is equals to 2a into displacement and displacement here is 75 meter which can be written as h so from here we will be root over since u square is zero initial velocity is zero here so this will be root over 2 a h if i substitute the values this will become 2 into 9 .8 into 75 and if you calculate this value then velocity with which the ball will strike with the ground is coming out as 38 .34 meter per second...

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