An object is place do = 7.000 cm from a diverging lens with radius of curvature R = 5.600 cm and an index of refraction of n = 1.750, What is the magnification of the object?
Added by Nuria W.
Step 1
600 cm and the index of refraction n = 1.750, and since the lens is diverging, R1 = -R and R2 = ∞ (since it is a diverging lens), the formula becomes: 1/f = (1.750 - 1) * (1/(-5.600) - 0) 1/f = 0.750 * (-0.1786) 1/f = -0.1339 f = -7.467 cm Show more…
Show all steps
Your feedback will help us improve your experience
Adriano Chikande and 51 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine the image distance di for an object do = 7.000 cm from a diverging lens with radius of curvature R = 5.600 cm and index of refraction 1.700. Express your answer as a positive quantity. What is the magnification m of the object? Be sure to insert the proper sign if needed. What is the nature of the image? inverted and smaller upright and smaller inverted and larger upright and larger
Adriano C.
Determine the image distance d for an object do = 7.900 cm from a diverging lens with a radius of curvature R = 6.320 cm and an index of refraction of 1.700. Express your answer as a positive quantity. What is the magnification of the object? Be sure to insert the proper sign if needed. What is the nature of the image? - Inverted and smaller - Upright and smaller - Inverted and larger - Upright and larger
Adi S.
A double-convex thin lens has surfaces with equal radii of curvature of magnitude 2.50 cm. Using this lens, you observe that it forms an image of a very distant tree at a distance of 1.87 cm from the lens. What is the index of refraction of the lens?
Kratika B.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD