An object is thrown. t seconds after it is thrown, its height is given by h(t) = -16t^2 + 256t + 100 feet The object reaches its highest point after seconds. The object's maximum height is feet.
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- Differentiating h(t) = 16t^2 + 256t + 100 with respect to t, we get h'(t) = -32t + 256. - Setting h'(t) = 0, we have -32t + 256 = 0. - Solving for t, we get t = 8. Show more…
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