An organism of the genotype A a B b C c was testcrossed to a...

An organism of the genotype $A a B b C c$ was testcrossed to a triply recessive organism (aabbcc). The genotypes of the progeny are in the following table. (a) Assuming simple dominance and recessiveness in each gene pair, if these three genes were all assorting independently, how many genotypic and phenotypic classes would result in the offspring, and in what proportion? (b) Answer part (a) again, assuming the three genes are so tightly linked on a single chromosome that no crossover gametes were recovered in the sample of offspring. (c) What can you conclude from the actual data about the location of the three genes in relation to one another?

Transcript

0:00 Hello.

00:01 So in this question, the part is, so we can arrive at the phenotypic and genotypic ratio by this fog method.

00:10 By fogged method as follows.

00:14 So we have, see, we have to cross this a, a, b and c and small c.

00:21 It is, it should be crossed with the small one a, a, b and c c here.

00:27 So here this a we can see that this a has this one, it will cross with, it may cross with this and also with b and b.

00:43 Yes, this is and it may come to this c and this b and this b also with c and c there.

00:53 Right.

00:54 So therefore in this case we will have this a.

00:58 A, b, c, a, a, b, c, c.

01:04 And again, a, a, b, c, or you can make the table also.

01:10 But this is a fog method, that fork, you know that fork, how the fog is look like.

01:16 So, in this case, now the b, b, c, that means a, a, b, b, then c, c, in the next one, a, a, b, b and c c c, a, a, b and c c c.

01:28 B and c c here now see in the next part this is small c now for this we have if we have to cross this a this a and a man it crossed with this b and b and b and again this b and b and also it crossed with if this capital c is small c and small c and small c like we are doing in both cases right now the now the ll is getting cheese now for this this part first it we can say that a a b b and c is formed and similarly a a b b small c small c form and here a a b b and c b b c is there and a ab b c is there and a ab b c is there so we can see that all these are different from each other so it is one it is one it is one it is one it is one one one one and one so therefore we can say that the the ratio for the genotypic and the phenotypic ratio is there that is one ratio one ratio one ratio one ratio one ratio one two three four five six seven and eight eight it is there hence, it is a phenotypic ratio and for the genotypic it is 8.

03:09 As we know, the dominant and recessive corrective here, formed in each gene pair...

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