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Hello everyone.
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In this question we have been given an unknown metal atom which is a and it is crystallized by means of a body centered cubic lattice.
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So bcc will be the type of crystallization which means body centered.
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So in the first part of the question we have to draw the metal unit cell and determine the number of atom in one unit cell.
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So first of all as we know that this is bcc type of unit cell.
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So there will be cubic unit cell and all the atoms will lie on the corner.
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So there is eight corners.
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So there will be eight atoms which is lying at the corner of the unit cell.
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And so this is bcc type.
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So one more atom is occupying in the body center positions.
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So number of atoms in one.
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One unit cell, one unit cell will be, first of all, we have corner, so eight corner multiply by contribution, so it will be 1 by 8, so this is 1 and in case of body center, which is lying at the center of the unit cell, so there is 1 and its contribution is 1, so there will be 1.
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So total of total number of atoms per unit cell...