An urn contains three red balls and two blue balls and four green balls. We draw two balls simultaneously from the urn. What is the probability that neither ball is red? a. 1/4 b. 13/36 c. 5/18 d. 5/12 e. None of the other answers is correct
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Step 1: Calculate the total number of ways to choose 2 balls out of 9 (3 red + 2 blue + 4 green) balls simultaneously using combination formula: \[ \binom{9}{2} = \frac{9!}{2!(9-2)!} = \frac{9 \times 8}{2 \times 1} = 36 \] Show more…
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