Question

Assuming D? and D? are identical diodes. If I = 0.5 mA what is the value of R in ?? Note use $I_D = I_S \cdot exp(\frac{V_D}{V_T})$ where $I_S = 5 \cdot 10^{-16}$ A

          Assuming D? and D? are identical diodes. If I = 0.5 mA what is the value of R in ??
Note use $I_D = I_S \cdot exp(\frac{V_D}{V_T})$ where $I_S = 5 \cdot 10^{-16}$ A

Assuming D? and D? are identical diodes. If I = 0.5 mA what is the value of R in ??
Note use ID = IS · exp((VD)/(VT)) where IS = 5 · 10^-16 A

Added by Celia M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert James Kiss

Step 1

We know that the current through the diodes is 0.5mA, and the voltage drop across a diode is typically around 0.7V. So, the voltage drop across D1 and D2 is: Vd = 0.5mA * 0.7V = 0.35V Show more…

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