Question

A proton in a particle accelerator moving with speed of 6.0!10^6 m/s through a magnetic field whose magnitude is 0.9 T experiences a magnetic force on 3.8 x 10^-13 N Find the the angle between the field and the proton's velocity. Where the charge of proton is q=e=+1.6!10^-19 C 60 37.42 26.1 33.2

          A proton in a particle accelerator moving with speed of 6.0!10^6 m/s through a magnetic field whose magnitude is 0.9 T experiences a magnetic force on 3.8 x 10^-13 N
Find the the angle between the field and the proton's velocity. Where the charge of proton is q=e=+1.6!10^-19 C

60
37.42
26.1
33.2

A proton in a particle accelerator moving with speed of 6.0!10^6 m/s through a magnetic field whose magnitude is 0.9 T experiences a magnetic force on 3.8 x 10^-13 N
Find the the angle between the field and the proton's velocity. Where the charge of proton is q=e=+1.6!10^-19 C

60
37.42
26.1
33.2

Added by Linda S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Aarya B

Step 1

A proton is moving through a magnetic field and experiences a magnetic force. We need to find the angle between the magnetic field and the proton's velocity. We are given the charge of the proton and its speed. We can use the formula for the magnetic force on a Show more…

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A proton in a particle accelerator moving with speed of 6.0 x 10^6 m/s through a magnetic field whose magnitude is 0.9 T experiences a magnetic force of 3.8 x 10^-13 N. Find the angle between the field and the proton's velocity. Where the charge of proton is q = +1.6 x 10^-19 C