Question

Angular Momentum In the instant of Fig. $11-41$ two particles move in an $x y$ plane. Particle $P_{1}$ has mass 6.5 $\mathrm{kg}$ and speed $v_{1}=2.2 \mathrm{m} / \mathrm{s},$ and it is at distance $d_{1}=1.5 \mathrm{m}$ from point $O$. Particle $P_{2}$ has mass 3.1 $\mathrm{kg}$ and speed $v_{2}=3.6 \mathrm{m} / \mathrm{s}$ , and it is at distance $d_{2}=$ 2.8 $\mathrm{m}$ from point $O .$ What are the (a) magnitude and (b) direction of the net angular momentum of the two particles about $O$ ?

          Angular Momentum
In the instant of Fig. $11-41$ two particles move in an $x y$ plane. Particle $P_{1}$ has mass 6.5 $\mathrm{kg}$ and speed $v_{1}=2.2 \mathrm{m} / \mathrm{s},$ and it is at distance $d_{1}=1.5 \mathrm{m}$ from point $O$. Particle $P_{2}$ has mass 3.1 $\mathrm{kg}$ and speed $v_{2}=3.6 \mathrm{m} / \mathrm{s}$ , and it is at distance $d_{2}=$ 2.8 $\mathrm{m}$ from point $O .$ What are the (a) magnitude and (b) direction of the net angular momentum of the two particles about $O$ ?

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Added by Ariel U.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sikandar Baig

05/23/2022

Step 1

Given: Distance $d_1 = 1.5 \, \text{m}$ Mass $m_1 = 6.5 \, \text{kg}$ Velocity $v_1 = 2.2 \, \text{m/s}$ Using the formula for angular momentum $L = r \times p$, where $r$ is the distance vector and $p$ is the linear momentum vector: Angular momentum of particle Show more…

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Angular Momentum In the instant of Fig. $11-41$ two particles move in an $x y$ plane. Particle $P_{1}$ has mass 6.5 $\mathrm{kg}$ and speed $v_{1}=2.2 \mathrm{m} / \mathrm{s},$ and it is at distance $d_{1}=1.5 \mathrm{m}$ from point $O$. Particle $P_{2}$ has mass 3.1 $\mathrm{kg}$ and speed $v_{2}=3.6 \mathrm{m} / \mathrm{s}$ , and it is at distance $d_{2}=$ 2.8 $\mathrm{m}$ from point $O .$ What are the (a) magnitude and (b) direction of the net angular momentum of the two particles about $O$ ?

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