The following reaction is at equilibrium in a closed 4L vessel:
N2(g) + 3H2(g) = 2NH3(g)
What will happen if the vessel volume is reduced to 3L? (Assume constant temperature)
A) The amounts of reactants and products will not change.
B) The equilibrium will shift to the left, producing more N2(g) and H2(g).
C) The amounts of both reactants and products will increase.
D) The amounts of both reactants and products will decrease.