00:02
In this problem, we are asked to determine the equivalent resistance of the below electric circuit.
00:14
Second, the voltage across r1 and between a ,b, the current through the r5 and the current through r2.
00:28
So first of all, we will find out the equivalent resistance for the electric circuit.
00:39
We can find out this is in parallel okay so this this as a whole as a parallel i'm just taking out this so it will be like for question number a we have this will be be circuit like this again this is our r2 and r4 are in parallel r2 and r4 are in parallel so that will be resistant okay so it will be r3 and again this is parallel to this okay so this is how this circuit is made so this is r5 and this is r1 all right so r1 r2 r4 parallel isn't parallel okay so this will become value of r2 is 12 as we know r2 r4 by r2 plus r4 this is the equivalent resistance for both parallel circuit both parallel registers sorry so it will be 12 into 6 by 12 plus 6 that will make as so this will be 4 so what is the value of this resistor? this will the value will be 4 .0.
02:48
Again, we will equalize.
02:52
We will just see how it becomes.
02:56
So it will again reduces into r1.
03:03
This is r1.
03:06
And this is 4.
03:13
4.
03:14
And 4 om and r3 will be in series so if we will solve this then this will be in addition so in series both are added so this this resistance becomes 4 plus r3 okay so now this is in parallel to this one more resistance is there that is r5 so we are just going very slow as we want to know how to find the equivalent resistance so again we can see here this this value 4 plus r3 and r5 in parallel so we will solve for it again so this will come as r1 this will be in parallel so what will be the answer? we will see this 4 plus r3.
04:29
This will be in parallel with r5.
04:34
So we will just take its value itself so that it will be more easy.
04:40
So what does it come as? this value comes as 4 plus r2.
04:52
Sorry, r3, sorry.
04:54
So r3's value is 4.
04:58
Okay, so this will become 8.
05:00
4 plus 4 8 then 8 and 8 so it will become as r equivalent becomes this to 4 plus r 3 parallel to r 5 so this both values are this is also 8 this is also 8 so we can directly solve it by 8 by 2 because 2 register we are talking about so this will be 4 or you can also simply calculate as 8 into 8, 8 plus 8.
05:50
So this will be the same value we will come across.
05:54
But actually this is the formula for parallel.
05:57
If we have same resistors, then we just, we just divide it by the value number of registers, r by n.
06:15
So this is our value.
06:17
So this value becomes now, this is our value.
06:23
This becomes as 4 om.
06:26
And r1 is what? r1 is 2 om.
06:34
Okay? so r1 is again 2 om.
06:37
So this will be again in series.
06:39
So this will make as again, this value becomes as r equivalent now equals to 2 plus 4 that is 6 o.
06:52
So this is our answer for part a.
07:02
Again, now we are going to part 2.
07:13
So for part b, we are asked to find out the voltage across r1.
07:25
So as we have already calculated before that this is.
07:29
R1 and this must be one more resistor connected equivalent we have calculated here let us see here what we have calculated as so this is 2 and this is 4 so we will take it as like this in the circuit so this is 2 oom and this is 4 om so it will come as we will just connect battery with it dc volt battery so this is 12 volt right this is a resistance and suppose we have we are asked to find out voltage between this point so this is a and this is b.
08:26
We are also asked to find out the voltage across this resistor r1 right so we even let us suppose this as ev1 and this is vab.
08:43
So we are asked to find out both the values...