Question

A binary operation * on a set S is said to be associative if and only if for any element a, b, c in S Select one: a. abc=cba b. ab=ba c. (ab)c=a(bc) d. none of these If S is a set having identity element "e" with respect to the binary operation * and corresponding to each element "a" in S, there exist an element "b" in S such that Select one: a. ab=ba=e b. a+b=b+a=e c. ae=be=e d. a/b=b/a=e

          A binary operation * on a set S is said to be associative if and only if for any element
a, b, c in S
Select one:
a. a*b*c=c*b*a
b. a*b=b*a
c. (a*b)*c=a*(b*c)
d. none of these
If S is a set having identity element "e" with respect to the binary operation * and
corresponding to each element "a" in S, there exist an element "b" in S such that
Select one:
a. a*b=b*a=e
b. a+b=b+a=e
c. a*e=b*e=e
d. a/b=b/a=e

A binary operation * on a set S is said to be associative if and only if for any element
a, b, c in S
Select one:
a. a*b*c=c*b*a
b. a*b=b*a
c. (a*b)*c=a*(b*c)
d. none of these
If S is a set having identity element "e" with respect to the binary operation * and
corresponding to each element "a" in S, there exist an element "b" in S such that
Select one:
a. a*b=b*a=e
b. a+b=b+a=e
c. a*e=b*e=e
d. a/b=b/a=e

Added by Meagan M.

Discrete Mathematics with Applications

Thomas Koshy 1st Edition

Chapter 2

Instant Answer

Solved by Expert Adi S

05/24/2023

Step 1

This means that for any elements a, b, and c in the set S, the order in which we perform the operation does not matter. We can check this by trying out the options given: a. a*b*c=c*b*a - This is not necessarily true for all binary operations, so it cannot be the Show more…

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A binary operation on a set S is said to be associative if and only if for any elements a, b, and c, Select one: a. a * (b * c) = (c * b) * a b. a * b * c = c * b * a c. (a * b) * c = a * (b * c) d. none of these If S is a set having an identity element "e" with respect to the binary operation * and corresponding to each element "a" in S, there exists an element "b" in S such that Select one: a. a * b = b * a = e b. a + b = b + a = e c. a * e = b * e = e d. a / b = b / a = e