Question

y = (5 - 2x)(1 - 4x) f(t) = (t/2) sen (4t - 1) Derive f(t) = 2 + e^-3 + f(x) = \frac{(-2x^2 + 4)}{(3x^2 - 6)} y = \sqrt{1 - \frac{\sqrt{x}}{4}} 

          y = (5 - 2x)(1 - 4x)
f(t) = (t/2) sen (4t - 1)
Derive f(t) = 2 + e^-3 +
f(x) = \frac{(-2x^2 + 4)}{(3x^2 - 6)}
y = \sqrt{1 - \frac{\sqrt{x}}{4}}
y = (5 - 2x)(1 - 4x) f(t) = (t/2) sen (4t - 1) Derive f(t) = 2 + e^-3 + f(x) = ((-2x^2 + 4))/((3x^2 - 6)) y = √(1 - (√(x))/(4))

Added by Nicole K.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Answer following derivatives y=(5-2x)(1-4x) f(t)=((t)/(2))sen(4t-1) Derive f(t)=2te^(-3t) f(x)=((-2x^(2)+4))/((3x^(2)-6)) y=sqrt(1-(sqrt(x))/(4)) y=5-2x4x F(+)=(+12sen(4+-1 F(+)=2+e-3+ F(x)=(-2x+4 (3x=-6) 1- Jx h
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Transcript

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00:01 Hello students, let us discuss the solution of this question.
00:03 Here in the question we have to find the first four derivative of h of t where h of t is equal to 7t to 2 minus 3 e raised to t.
00:14 Now let us discuss the solution of this question.
00:17 We know that differentiation with respect to x of x raise to n is equal to n x x raised to n minus 1.
00:26 Also differentiation of e raised to x.
00:31 Is equal to e raise 2x also the differentiation of the differentiation of two functions u and v u plus v is equal to first of all let us take differentiation of u plus differentiation of v where u and v are the functions of x like this now we are going to use these three formulas to solve this first second and third and four derivative of h of t so h of t is equal to h of t is equal to c it is 7 t square minus 3 e 7 t raised to 2 minus 3 e raised to t now differentiate with respect to t so the first derivative h prime of t is equal to 7 multiplied by 2 t minus 3 e raised to t so h prime of t is equal to or the first derivative of h with respect to t is 14 t minus 3e raised to t.
01:54 Now let us take the second derivative.
01:57 The second derivative of h of t is the second derivative of h of t is differentiation of this...
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