Answer parts a and b. a. n(A U B) = 28, n(A ∩ B) = 18, and n(B) = 23, find n(A). b. If n(A) = 13, n(B) = 18, and n(A ∩ B) = 6, find n(AUB). a. n(A) = b. n(AUB) =
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We want to find $n(A)$. We can use the principle of inclusion-exclusion: $n(A \cup B) = n(A) + n(B) - n(A \cap B)$ Plugging in the given values, we have: $28 = n(A) + 23 - 18$ $28 = n(A) + 5$ $n(A) = 28 - 5$ $n(A) = 23$ Show more…
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