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Problem 1. (2.20.2) Find $f'(z)$ for the following functions. 1. $f(z) = 3z^2 - 2z + 4$; 2. $f(z) = (2z^2 + i)^5$; 3. $f(z) = \frac{z-1}{2z+1}$, $z \neq -\frac{1}{2}$.

          Problem 1. (2.20.2) Find $f'(z)$ for the following functions.
1. $f(z) = 3z^2 - 2z + 4$;
2. $f(z) = (2z^2 + i)^5$;
3. $f(z) = \frac{z-1}{2z+1}$, $z \neq -\frac{1}{2}$.

Problem 1. (2.20.2) Find f'(z) for the following functions.
1. f(z) = 3z^2 - 2z + 4;
2. f(z) = (2z^2 + i)^5;
3. f(z) = (z-1)/(2z+1), z ≠ -(1)/(2).

Added by Catalina R.

Calculus: Early Transcendentals

James Stewart 8th Edition

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For the function f(z) = 3z^2 - 2z + 4, we can simply substitute any value of z into the equation to find f(z). For example, if we substitute z = 2, we have: f(2) = 3(2)^2 - 2(2) + 4 = 3(4) - 4 + 4 = 12 - 4 + 4 = 12 So, f(2) = 12. Show more…

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Problem 1.2.20.2: Find f(z) for the following functions 1. f(z) = 3z^2 - 2z + 4; 2. f = 22 + i5 3. f = 2 + 12 -

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