Q: A solution of hydrofluoric acid has a molar concentration of 0.0100 mol/L. What is the pH of this solution? [3]
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0100 M, [H+] = 0, [F-] = 0. Let x = [H+] at equilibrium. Ka = 6.6 × 10^-4 = x^2/(0.0100 − x). First approximate: x ≈ sqrt(Ka·0.0100) = sqrt(6.6×10^-4 × 1.00×10^-2) = 2.57×10^-3 M (percent ionization ≈ 25.7% >5%, so approximation is not sufficiently accurate). Show more…
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