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In stoichiometry, we relate the quantities of the substances that are involved in a chemical reaction.
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In this problem, we have the reaction between silver nitrate and sodium chloride.
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Chloride to form silver chloride and sodium nitrate according to this balance equation.
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If the reaction involves 4 .1 grams of silver nitrate to react with 3 .5 grams of sodium chloride to form 4 .8 grams of silver chloride, we wish to find the percent yield of the reaction.
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So we take note that from the coefficients of the balance equation for one mole of each of the reactant, we have one mole of the product that is formed.
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So that follows that the moles of agcl that is formed will be equal to the moles of whichever reactant comes in smaller moles.
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So let's find the moles of agno3 and nacl first by dividing their mass by their molar masses.
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So for agno3, the molar mass is equal to 169 .9.
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So we get 4 .1 divided by 169 .9 that gives us 0 .0241.
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Whereas that of agcl, we have, or sorry, that is for nacl, i mean, we have 3 .5 divided by 58 .5, which gives us 0 .0598.
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So since the moles of agno3 is smaller than that of the nacl, agno3 is the limiting reactant...