Question

Antimony (Sb) has two naturally occurring isotopes. The mass of Sb-121 is 120.904 amu, and the mass of Sb-123 is 122.904 amu. If the average atomic mass of antimony is 121.760 amu, find the percentage abundance of the heavier isotope to within two decimal places.

Name: antimony sb has two naturally occurring isotopes the mass of sb 121 is 120904 amu and the mass of sb 123 is 122904 amu if the average atomic mass of antimony is 121760 amu find the percentag 75485
Uploaded: 2020-12-04T05:08:10-08:00
Duration: 1 min 48 s
Channel: Ronald Prasad
Description: antimony sb has two naturally occurring isotopes the mass of sb 121 is 120904 amu and the mass of sb 123 is 122904 amu if the average atomic mass of antimony is 121760 amu find the percentag 75485

          Antimony (Sb) has two naturally occurring isotopes. The mass of Sb-121 is 120.904 amu, and the mass of Sb-123 is 122.904 amu. If the average atomic mass of antimony is 121.760 amu, find the percentage abundance of the heavier isotope to within two decimal places.

Added by Nicole C.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ronald Prasad

12/04/2020

Step 1

Therefore, the percentage abundance of the lighter isotope Sb-121 will be \( 1 - x \). Show more…

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Antimony (Sb) has two naturally occurring isotopes. The mass of Sb-121 is 120.904 amu, and the mass of Sb-123 is 122.904 amu. If the average atomic mass of antimony is 121.760 amu, find the percentage abundance of the heavier isotope to within two decimal places.