4. As a capacitor is being charged, the potential difference Delta V across the plates and the charge Q stored on the capacitor are measured. The data are shown in the graph of Delta V as a function of Q shown above. The work needed to increase the charge on the capacitor from 10.0 mu C to 15.0 mu C is most nearly (A) 0 (B) 12.5 mu J (C) 22.5 mu J (D) 62.5 mu J (E) 125 mu J
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The work done (W) on a capacitor is given by the formula: W = 1/2 * Q * ΔV where Q is the charge and ΔV is the potential difference. From the graph, we can see that the potential difference ΔV increases linearly with the charge Q. This means that the slope of Show more…
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24.16. In Fig. 24.8 $\mathrm{a}$ , let $C_{1}=$ $3.00 \mu \mathrm{F}, C_{2}=5.00 \mu \mathrm{F}$ , and $V_{a b}=$ $+52.0 \mathrm{V}$ . Calculate (a) the charge on each capacitor and $(\mathrm{b})$ the potential difference across each capacitor.
A 40-pF capacitor is charged to a potential difference of 500 V. Its terminals are then connected to those of an uncharged 10-pF capacitor. Calculate: (a) the original charge on the 40-pF capacitor; (b) the charge on each capacitor after the connection is made; and (c) the potential difference across the plates of each capacitor after the connection.
In Fig, 24.9 $\mathrm{a}$ . let $C_{1}=$ $3.00 \mu \mathrm{F}, \quad C_{2}=5.00 \mu \mathrm{F}, \quad$ and $V_{a b}=+52.0 \mathrm{V}$ . Calculate $(\mathrm{a})$ the charge on each capacitor and $(b)$ the potential difference across each capacitor.
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