Apply the stronger form of l'Hospital's Rule to find the limit. $$ \lim _{x \rightarrow 2} \frac{x^{2}-4 x+4}{x^{3}-12 x+16} $$
Added by Steven S.
Step 1
We can see that as $x$ approaches 2, both the numerator and denominator approach 0, so the limit is of the form $\frac{0}{0}$. Show more…
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