The width is given by:
$$
h = \frac{b - a}{n}
$$
where $a$ is the lower limit, $b$ is the upper limit, and $n$ is the number of subintervals. In this case, we have $a = 1$, $b = 2$, and $n = 4$. So,
$$
h = \frac{2 - 1}{4} = \frac{1}{4}
$$
Now, let's
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