Question

Are the functions $y_1(t) = 5t^2$, $y_2(t) = t^2$ a fundamental set of solutions of $t^2y'' + 2ty' - 6y = 0$? a. Yes, they are solutions and their Wronskian is not zero b. No since their Wronskian is equal to zero C. No, since only $y_2(t)$ is a solution of the given equation d. No, since only $y_1(t)$ is a solution of the given equation

          Are the functions $y_1(t) = 5t^2$, $y_2(t) = t^2$ a fundamental set of solutions of $t^2y'' + 2ty' - 6y = 0$? 
a. Yes, they are solutions and their Wronskian is not zero
b. No since their Wronskian is equal to zero
C. No, since only $y_2(t)$ is a solution of the given equation
d. No, since only $y_1(t)$ is a solution of the given equation

Are the functions y1(t) = 5t^2, y2(t) = t^2 a fundamental set of solutions of t^2y” + 2ty' - 6y = 0?
a. Yes, they are solutions and their Wronskian is not zero
b. No since their Wronskian is equal to zero
C. No, since only y2(t) is a solution of the given equation
d. No, since only y1(t) is a solution of the given equation

Added by David J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

06/05/2023

Step 1

Step 1: To determine if the functions y(t) = 5t^2 and y(t) = t^2 are solutions of the given equation t^2y + 2ty - 6y = 0, we need to substitute these functions into the equation and check if it holds true. Show more…

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Are the functions y,t)= 5t2, yt)=t2 a fundamental set of solutions of t2y+ 2ty - 6y=0? O a. Yes, they are solutions and their Wronskian is not zero b.No since their Wronskian is equal to zero O c. No, since only y , (t) is a solution of the given equation O d. No, since only y , (t) is a solution of the given equation