Area inside the graph $r = 2$ and outside $r = 3 + 3 \sin \theta$
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$2 = 3 + 3\sin\theta$ $3\sin\theta = -1$ $\sin\theta = -\frac{1}{3}$ $\theta = \arcsin(-\frac{1}{3}) \approx -0.3398$ and $\theta = \pi - \arcsin(-\frac{1}{3}) \approx 3.4814$ Show more…
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