As an aid in working this problem, consult Concept Simulation 20.5. Determine the power supplied to the 5.0 ? resistor in the circuit shown in the drawing. (R1 = 4.0 ?, R2 = 5.0 ? and V1 = 15 V.) W Read the eBook Section 20.8 Circuits Wired Partially in Series and Partially in Parallel
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Adi S.
Calculate the current running through resistor Rc in the circuit shown in the figure. Give your answer in milliamps. Assume the following values for the circuit elements: ε = 1.50 V, Ra = 1.00 Ω, Rb = 4.00 Ω, Rc = 8.00 Ω, Rd = 3.00 Ω, Re = 5.00 Ω, Rf = 9.75 Ω.
Sahil K.
For the circuit shown find the current in each resistor and the current drawn from the 40 - $V$ source. Notice that the p.d. from $a$ to $b$ is $40 \mathrm{~V}$. Therefore, the p.d. across each resistor is $40 \mathrm{~V}$. Then, $$ I_{2}=\frac{40 \mathrm{~V}}{2.0 \Omega}=20 \mathrm{~A} \quad I_{5}=\frac{40 \mathrm{~V}}{5.0 \Omega}=8.0 \mathrm{~A} \quad I_{8}=\frac{40 \mathrm{~V}}{8.0 \Omega}=5.0 \mathrm{~A} $$ Because $I$ splits into three currents: $$ I=I_{2}+I_{5}+I_{8}=20 \mathrm{~A}+8.0 \mathrm{~A}+5.0 \mathrm{~A}=33 \mathrm{~A} $$
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