Question

y'' - 2y' - 3y = e^{2t}; y(0) = 0, y'(0) = 0 Solve the initial value problem with the help of Laplace transform

          y'' - 2y' - 3y = e^{2t}; y(0) = 0, y'(0) = 0
Solve the initial value problem with the help of Laplace transform

Added by Gregory A.

Calculus: Early Transcendentals

James Stewart 8th Edition

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As fast As possible and promise you upvote look at the picture not the text y^('')-2y^(')-3y=e^(2^(^()))2t;y(0)=0,y^(')(0)=0 Solve the initial value problem with the help of Laplace transform y"-2y`-3y = e2^2t ; y(0) = 0,y'(0) = 0 Solve the initialvalue problem with the help of Laplace transform