00:01
In this question, we have given details of cincinnati employees and pittsburgh employees.
00:15
So now, randomly 35 employees were taken and it was found that they travel a mean of 370 miles per month and their standard deviation or we can say population standard deviation is equal to 30 miles.
00:42
Whereas, randomly 40 pittsburgh employees were taken and it was found that they travel a mean of 380 miles per month and their standard deviation is equal to 26 miles.
01:07
So here we have to find at the 0 .05 significance level which means our level of significance is equal to 0 .05, we have to find is there a difference in mean number of miles travelled per month between cincinnati and pittsburgh employees.
01:24
So first of all, we will write the hypothesis.
01:28
Our null hypothesis says that there is no difference in the mean number of miles travelled per month between cincinnati and pittsburgh employee and alternative hypothesis says which is just opposite of this null hypothesis that there is a difference between number of miles travelled per month between cincinnati employees and pittsburgh employee and clearly we can see that this is a two -tailed test.
02:05
Now in the next step, we will find the z calculated value which is equal to sample mean for pittsburgh employee minus sample mean of cincinnati employee whole divided by square root of standard deviation of cincinnati employee square divided by sample size of cincinnati employee plus standard deviation of pittsburgh employee square divided by sample size of pittsburgh employees...