Question

As reported in Trends in Television, the proportion of US households who have at least one VCR is 0.479. If 10 households are selected at random, without replacement, from all US households, what is the (approximate) probability that the number having at least one VCR is no more than 7 but at least 5.00. Be sure to use many decimal places in your calculations (at least 4), but report your answer to three decimal places.

Name: as reported in trends in television the proportion of us households who have at least one vcr is 0479 if 10 households are selected at random without replacement from all us households what 69671
Uploaded: 2022-04-09T06:24:32-08:00
Duration: 1 min 52 s
Channel: Rashmi Sinha
Description: as reported in trends in television the proportion of us households who have at least one vcr is 0479 if 10 households are selected at random without replacement from all us households what 69671

          As reported in Trends in Television, the proportion of US
households who have at least one VCR
is 0.479.
If 10 households are selected at random,
without replacement, from all US households, what is the
(approximate) probability that the number having at least one VCR
is no more than 7 but at
least 5.00. Be sure to use many decimal
places in your calculations (at least 4), but report your answer to
three decimal places.

Added by Justin B.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Rashmi Sinha

04/09/2022

Step 1

479)^5 * (1-0.479)^(10-5) = 252 * (0.479)^5 * (0.521)^5 ≈ 0.244 Show more…

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As reported in Trends in Television, the proportion of US households who have at least one VCR is 0.479. If 10 households are selected at random, without replacement, from all US households, what is the (approximate) probability that the number having at least one VCR is no more than 7 but at least 5.00. Be sure to use many decimal places in your calculations (at least 4), but report your answer to three decimal places.