Question

As the experiment was carried out under constant pressure, the heat flow for the process is equal to the change in enthalpy for the process. The enthalpy of fusion (melting) for ice is calculated as follows: Enthalpy of fusion for ice in J/g = +4971.90 J/14.66 g = 339.147 J/g. To convert this value to other units: a. in kJ/g b. in kJ/mol c. in cal/g d. in kcal/mol The accepted value for the enthalpy of fusion of water (in kJ/mol) is 6.01 kJ/mol.

Name: as the experiment was carried out under constant pressure heat flow for the process is equal to the change in enthalpy for the process enthalpy of fusion melting for ice in jg 497190j1466g 3 47552
Uploaded: 2023-08-08T05:25:32-08:00
Duration: 2 min 54 s
Channel: Madhur L
Description: as the experiment was carried out under constant pressure heat flow for the process is equal to the change in enthalpy for the process enthalpy of fusion melting for ice in jg 497190j1466g 3 47552

          As the experiment was carried out under constant pressure, the heat flow for the process is equal to the change in enthalpy for the process. The enthalpy of fusion (melting) for ice is calculated as follows: Enthalpy of fusion for ice in J/g = +4971.90 J/14.66 g = 339.147 J/g. 

To convert this value to other units:
a. in kJ/g
b. in kJ/mol
c. in cal/g
d. in kcal/mol

The accepted value for the enthalpy of fusion of water (in kJ/mol) is 6.01 kJ/mol.

Added by Andrea S.

Holt: Modern Chemistry

Mickey Sarquis, Jerry L. Sarquis 1st Edition

Chapter 10

Instant Answer

Solved by Expert Madhur L

08/08/2023

Step 1

To convert J/g to kJ/g, we need to divide by 1000: 339.147 J/g ÷ 1000 = 0.339147 kJ/g b. To convert J/g to kJ/mol, we need to use the molar mass of water, which is 18.015 g/mol: 339.147 J/g × (1 kJ/1000 J) × (1 mol/18.015 g) = 0.0188 kJ/mol c. To convert J/g to Show more…

Show all steps

Thanks for your feedback!

As the experiment was carried out under constant pressure, the heat flow for the process is equal to the change in enthalpy for the process. The enthalpy of fusion (melting) for ice is calculated as follows: Enthalpy of fusion for ice in J/g = +4971.90 J/14.66 g = 339.147 J/g. To convert this value to other units: a. in kJ/g b. in kJ/mol c. in cal/g d. in kcal/mol The accepted value for the enthalpy of fusion of water (in kJ/mol) is 6.01 kJ/mol.