When demonstrating that $\lim_{x \to 2} (3x + 2) = 8$ with $\epsilon = 0.5$, which of the following $\delta$-values suffices? [There may be MORE THAN ONE correct answer, so select all that apply] $\delta = 0.33333333333333$ $\delta = 0.027777777777778$ $\delta = 0.055555555555556$ $\delta = 0.18333333333333$
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5, we need to find a value of δ such that if |x-3|<δ, then |(3+2)-8|<0.5. Let's start by simplifying the expression |(3+2)-8|<0.5: |5-8|<0.5 |-3|<0.5 3<0.5 This is not true, so the value 0.33333333333333 does not suffice. Now let's try the value Show more…
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