Assume ls = 810-16A, V+ = 100, V+ = 26mV, and VA = 0. For the circuit shown below and for I = 0.5mA, the value of the transconductance is 10 Vcc = 2V. Hi Q1 VB Select one: Oa. 115.38mA/V Ob. 38.46mA/V Oc. 76.92mA/V Od. 19.23mA/V Oe. None of these
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We know that VA = 0 and V+ = 100, so the voltage drop across the resistor R1 is 100 - 0 = 100V. Since I = 0.5mA, we can use Ohm's Law to find the resistance R1: R1 = V/I = 100V / 0.5mA = 200kΩ. Show more…
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