Assume that the monthly worldwide average number of airplaine crashes of commercial airlines is 2.2. What is the probability that there will be (a) less than 2 such accidents in the next month? (b) at most 2 such accidents in the next 3 months? (c) exactly 6 such accidents in the next 4 months?
Added by Justin B.
Step 1
2$. The probability of less than 2 accidents in the next month is the sum of the probabilities of 0 and 1 accidents: $P(X < 2) = P(X = 0) + P(X = 1)$ Using the formula for the Poisson distribution: $P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}$ We have: $P(X < Show more…
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