Assume that $x = x(t)$ and $y = y(t)$. Let $y = x^3 + 1$ and $\frac{dx}{dt} = 4$ when $x = 3$. Find $\frac{dy}{dt}$ when $x = 3$.

          Assume that $x = x(t)$ and $y = y(t)$. Let $y = x^3 + 1$ and $\frac{dx}{dt} = 4$ when $x = 3$.

Find $\frac{dy}{dt}$ when $x = 3$.

Added by Dana P.

James Stewart 8th Edition

Instant Answer

07/05/2023

Step 1

$$\frac{dy}{dt} = 3x^2 \frac{dx}{dt}$$ Show more…

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Assume that x = x(t) and y = y(t). Let y = x³ + 1 and $$\frac{dx}{dt}=4$$ when x = 3. Find $$\frac{dy}{dt}$$ when x = 3.

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