00:01
Hello students, let's begin with this question.
00:02
In this question, we have to find out the weight percentage of the acetic acid.
00:09
Now, in our question, some data is given and also in this question, firstly we have to write the what will the equation form? here, this acidic acid react with the anewatch and it will form a ch3, c -o -n -a plus water.
00:26
Now here, this is the balanced equation.
00:28
One mole of acetic acid react with the one mole of fetic acid.
00:30
Nuh.
00:31
Now some data is given.
00:33
Volume of nuh is given which is equals to 28 .95 ml.
00:41
So when we converted into liter, it will come 1ml is equal to 0 .001 liter.
00:47
So volume of nuh, this comes to be 0 .02895 liter and also in the question, molarity.
01:01
Of nuh is given which is equal to 0 .1346 molar.
01:09
Now we have molarity and volume so we can calculate the number of moles of nuh so moles of nuh is equal to this can be calculated by multiplying the volume with the molarity.
01:26
So now substitute values in this formula so so volume is 0 .02895 liter multiply by 0 .1346 molar.
01:38
So here we get the moles.
01:40
These moles comes to be 0 .00389 moles.
01:46
Now, according to the law of equivalence, this law is applied here because here equal moles of n -o -h and acetic acid is there...