00:01
So here we have a transmission line problem, and we are asked to solve for our attenuation constant first.
00:06
We are given our corresponding inductance, conductivity, frequency, resistance, and capacitance.
00:13
So let's write our equation for attenuation constant.
00:16
Attenuation constant a has an equation in which a constant is equal to resistance over 2 times radical capacitance over inductance plus capacitance over.
00:31
Excuse me, our conductance over two times radical of our inductance over capacitance.
00:41
So let's go ahead and substitute our values in.
00:45
And alpha is equal to resistance .15 oms over two times our radical of capacitance over inductance.
00:55
So we want to make sure we have the rate conversion factor because we're given capacitance in terms of picofarad and our inductance in terms of micro henry.
01:08
And see here we have those conversion factors and we're going to get our conductance over 2 times our radical of inductance over capacitance.
01:21
And here we are.
01:22
So computing this, we get that our constant is equal to 1 .5646 times 10 to the negative 3rd.
01:35
And so this is part a.
01:40
If we go to calculate our phase constant, let's go ahead and write that formula down.
01:47
So our phase constant beta is equal to omega angular frequency times our conductance or excuse me inductance times capacitance.
01:58
So regard or recall that our equation for omega angular frequency or angular velocity angular frequency sometimes you may see omega written as a term, but here we're going to refer to it as angular frequency.
02:14
So angular frequency, equation of 2 pi f.
02:18
So when we substitute our omega value here, it's going to be 2 pi times our frequency given as 93 megahertz...