00:01
In this question, there's a letter that's making an angle that's placed against a wall and then making an angle 30 degrees from above the floor, horizontal floor.
00:13
And then at this instance, points b at the top of the ladder is moving down at 4 feet per second and acceleration 2 feet per second downward per second square downward.
00:25
Okay, and we need to determine the acceleration of point a and then and the lattice angular acceleration at this instance.
00:38
Okay, so we notes that va is to the left.
00:56
Okay, so likewise, the acceleration of point a will also be to the left.
01:04
So you can actually determine the instantaneous center of zero velocity which will be somewhere here.
01:15
This is the ic.
01:17
So we want this distance, which is 16 cosine degrees.
01:24
We can use this distance to determine omega of ab.
01:29
So omega ab is vb.
01:34
Vb divided by r i see to b.
01:39
Okay so this is 4 divided by 16 cosine 30 degrees.
01:51
Okay again it's going to move clockwise.
01:57
So this is going to be 1 over 2 root 3.
02:07
Okay this is equal to 0 .289.
02:11
Radiance per second okay then we can use the relative acceleration equation a a is a b plus alpha a b cross r b relative to a minus omega a b square r b relative to a okay so a b is so this is minus a a a a in the i direction ab is minus 2j, alpha ab is minus alpha ab, is minus alpha ab, k, cross rb relative to a will be minus 16, cosine 30 degrees i, plus sine 30 degrees j...