00:01
Hi, here we have to calculate the equilibrium concentration of one of the products.
00:05
Now, here decomposition of c3h6 is happening.
00:08
So firstly we are given with moles of c3h6 that is equal to 0 .875 mole.
00:17
So now first we have to calculate the concentration.
00:19
So concentration is equal to moles over volume, that is in form of molarity.
00:24
So, concentration of c3h6 is equal to, now moles is 0 .875.
00:31
0 .875 mole divided by volume is 1 .0 litre that is equal to 0 .875 molar.
00:40
Now the decomposition reaction takes place as 2 molecules of c3h6 gaseous gives c2h4 gaseous plus c4h8 gaseous.
00:59
Now using i stable, initially, that is, i stands for initial concentration, concentration of this is 0 .875 molar, and these concentrations are 0.
01:13
So now c stands for change in concentration, that is, is equal to minus 2c for this and plus c for each of these...