At a particular temperature, the solubility of NO₂ in water is 0.0350 M when the partial pressure is 0.0800 atm. What will the solubility (in M) be when the partial pressure of NO₂ is 1.72 atm?
Added by Christopher L.
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The formula is given by: \[ S_1 / P_1 = S_2 / P_2 \] where \( S_1 \) and \( S_2 \) are the solubilities at pressures \( P_1 \) and \( P_2 \) respectively. Show more…
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