Question

9 At what point do the following lines in $\mathbb{R}^3$ intersect? $l_1: \ (x, y, z) = (3, 1, 2) + s(1, 0, 2), \ s \in \mathbb{R}$ $l_2: \ (x, y, z) = (2, -1, -4) + t(0, 1, 2), \ t \in \mathbb{R}$ Select one alternative: $\circ \ (5, 1, 6)$ $\circ \ (-1, 2, 0)$ $\circ \ (2, 1, 0)$ $\circ \ (2, 0, -2)$

          9
At what point do the following lines in $\mathbb{R}^3$ intersect?
$l_1: \ (x, y, z) = (3, 1, 2) + s(1, 0, 2), \ s \in \mathbb{R}$
$l_2: \ (x, y, z) = (2, -1, -4) + t(0, 1, 2), \ t \in \mathbb{R}$
Select one alternative:
$\circ \ (5, 1, 6)$
$\circ \ (-1, 2, 0)$
$\circ \ (2, 1, 0)$
$\circ \ (2, 0, -2)$

9
At what point do the following lines in ℝ^3 intersect?
l1: (x, y, z) = (3, 1, 2) + s(1, 0, 2), s ∈ℝ
l2: (x, y, z) = (2, -1, -4) + t(0, 1, 2), t ∈ℝ
Select one alternative:
∘ (5, 1, 6)
∘ (-1, 2, 0)
∘ (2, 1, 0)
∘ (2, 0, -2)

Added by Dana C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sanchit Jain

Step 1

First, let's simplify the equations: 1: x, y, z = 3, 1, 2 + √1, 0, 2sER x = 3 y = 1 z = 2 + √1 = 2 + 1 = 3 2: x, y, z = 2 - 1 - 4 + t0, 1, 2teR x = 2 - 1 - 4 + t = -3 + t y = 1 z = 2 Now, let's set the x, y, and z values equal to each other and Show more…

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At what point do the following lines in IR intersect? 1: x, y, z = 3, 1, 2 + âˆš1, 0, 2sER l2: x, y, z = 2 - 1 - 4 + t0, 1, 2teR Select one alternative: O 5, 1, 6 O -1, 2, 0 O 2, 1, 0 O 0, 2, -2