At what points on the given curve x = 2t^3, y = 4 + 40t - 11t^2 does the tangent line have slope 1? (x, y) = ( ) (smaller x-value) (x, y) = ( ) (larger x-value)
Added by Nicolas B.
Close
Step 1
Step 1: Calculate dy/dt Given Y = 4 + 40t + 11t^2, differentiate with respect to t: dy/dt = 40 + 22t Show more…
Show all steps
Your feedback will help us improve your experience
Suman K and 78 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
At what points on the given curve x = 2t^3, y = 4 + 20t - 13t^2 does the tangent line have slope 1? (x, y) = ( ) (smaller x-value) (x, y) = ( ) (larger x-value)
Nakshathra M.
At what points on the given curve x = 2t^3, y = 2 + 40t - 11t^2 does the tangent line have slope 1? (x,y) = (3.9) (smaller x-value) (x,y) = (34.8) (larger x-value)
Chandra J.
Find the slope of the tangent line to the curve $y=1 / \sqrt{x}$ at the point where $x=4 .$
Derivatives
Tangents and the Derivative at a Point
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD