The plane that passes through the point (0, -2, 2) and is perpendicular to both $2x + 3y + 5z = -20$ and $4y - x + 5z = -22$ has \textit{implicit equation.}
Added by Lisa J.
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To find the direction vector of a plane, we can look at the coefficients of x, y, and z in the equation of the plane. For the first plane, 2x + 3y + 5z = -29, the direction vector is <2, 3, 5>. For the second plane, 4y - x + 5z = -22, the direction vector is Show more…
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