If an object is dropped from a 155-foot-high building, its position (in feet above the ground) is given by $s(t) = -16t^2 + 155$, where $t$ is the time in seconds since it was dropped (a) What is its velocity 1 second after being dropped? (b) When will it hit the ground? (c) What is its velocity upon impact? (a) The object's velocity 1 second after being dropped is $oxed{}$ $ rac{ft}{sec}$ (Simplify your answer)
Added by Alexander C.
Close
Step 1
The position of the dropped object is given by the equation s(t) = -16t² + 155, where s(t) is the height above ground (in feet) and t is time (in seconds). Show more…
Show all steps
Your feedback will help us improve your experience
Sufiyan Alam and 78 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A body is dropped from a height of 320m. The acceleration due to gravity is 10m/s^2. a) How long will it take to reach the ground? b) What is the velocity with which it strikes the ground?
Sufiyan A.
An object is dropped from a height. a) Describe its velocity as its falls to the ground. b) Describe its acceleration as it falls to the ground.
Adi S.
A ball is dropped from a height of 100m. (a)How long does it take for the ball to hit the ground? (b) at what velocity will it hit the ground?
Madhur L.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD