00:01
So, in this question we have given a arrangement of capacitors like this.
00:05
These two capacitors are in series and disconnected with the parallel one and another is a series with all the combination this is and this connected in the battery of voltage v, ok.
00:18
Now, this is the c 1, this is c 2, this is c 3 and this is c 4.
00:22
The values of c 1, c 2 and c 3 is equal c 1, c 2 and microfarad and value of c 4 equal to 75 .6 microfarad.
00:35
First of all we have to find the potential across this 4.
00:38
So, what we can do first that first of all we have to find the net capacitance.
00:42
So, these two are in series combination.
00:45
So, i am just assuming equivalent as c dash c 1, c 2 by c 1 plus c 2.
00:50
So, values of c 1 is equal to 59 .8 square because both are same.
00:56
So, here 2 times of 59 .8.
00:58
So, finally, i will have 29 .9 microfarad.
01:03
This is the c dash.
01:04
Now, this c dash and this c 3 is in series combination sorry parallel combination.
01:09
So, it will c double dash 10 29 .9 plus 59 .8.
01:15
So, finally, i will have the answer is 89 .7 microfarad.
01:19
Now, moving on this value this and this complete is in series combination.
01:23
So, i will find c equivalent is equal to simple 75 .6 into 89 .7 divide by 75 .6 plus 89 .7 and finally, i will have the answer is 41 .02 microfarad.
01:38
This is the value of c equivalent.
01:40
Now, moving on the total charge...