For the numerator, we have $\sqrt{7n^8 - 17 + 6n^3 - 5}$. The highest power of $n$ inside the square root is $n^8$. So, the effective highest power of $n$ in the numerator is $\sqrt{n^8} = n^4$.
For the denominator, we have $\sqrt{17n + 5 + 3n^4 + 20n^2}$. The
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