Question

(b) In an experiment to measure the acceleration due to gravity g, two values, 972 cm/s? and 967 cm/s\deg , aredetermined. Find (1) the percent difference of the measurements, (2) the percent error of each meas-urement, and (3) the percent error of their mean. (Accepted value: g = 980 cm/s?.)

Name: b in an experiment to measure the acceleration due to gravity g two values 972 cms and 967 cmsdeg aredetermined find 1 the percent difference of the measurements 2 the percent error of each 58933
Uploaded: 2022-09-14T14:19:22-08:00
Duration: 3 min 6 s
Channel: Khoobchandra Agrawal
Description: b in an experiment to measure the acceleration due to gravity g two values 972 cms and 967 cmsdeg aredetermined find 1 the percent difference of the measurements 2 the percent error of each 58933

          (b) In an experiment to measure the acceleration due to gravity g, two values, 972 cm/s? and 967 cm/s\deg , aredetermined. Find (1) the percent difference of the measurements, (2) the percent error of each meas-urement, and (3) the percent error of their mean. (Accepted value: g = 980 cm/s?.)

Added by Peter C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

09/14/2022

Step 1

To find the percent difference, we first need to calculate the absolute difference between the two measurements: \[ \text{Difference} = |972 \text{ cm/s}^2 - 967 \text{ cm/s}^2| = 5 \text{ cm/s}^2 \] Next, we divide this difference by the average of the two Show more…

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(b) In an experiment to measure the acceleration due to gravity g, two values, 972 cm/s? and 967 cm/s\deg , aredetermined. Find (1) the percent difference of the measurements, (2) the percent error of each meas-urement, and (3) the percent error of their mean. (Accepted value: g = 980 cm/s?.)