b) Suppose \frac{4t-3}{t} \leq f(t) \leq \frac{4t^5+7}{t^5-3} when t > 92. Determine \lim_{t \to \infty} f(t).
Added by Lori F.
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This gives us 4 - 3/t <= f(t) <= 4t^4/t^5 + 7/t^5 - 3/t. Show more…
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