(b) The point P = (2, -1, $z_0$) lies on the surface $2z - \ln(2x^2 + y^2) + \ln 9 = 0$. Determine $z_0$ and find an equation for the tangent plane to the surface at the point P.
Added by Rodrigo M.
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We are given that P = (2, -1, z), and the equation of the surface is 2z - ln(2x^2 + y^2) + ln 9 = 0. Substitute the x and y values from point P into the equation to solve for z. Show more…
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